Pandas dataframe, get the row and index for a column meeting certain conditions

I have the below df:

import pandas as pdimport numpy as npoutput =  [['Owner', 'Database', 'Schema', 'Table', 'Column', 'Comment', 'Status'], ['', 'DEV', 'AIRFLOW', 'TASK_INSTANCE', '_LOAD_DATETIME', 'Load datetime'], ['', 'DEV', 'AIRFLOW', 'TEST', '_LOAD_FILENAME', 'load file name', 'ADDED'],['', 'DEV', 'AIRFLOW', 'TEST_TABLE', 'TEST_COL', 'COMMENT TEST'],]df = pd.DataFrame(output[1:], columns=output[0])query_list = []empty_status_idx = []for index, row in df.iterrows():    if row['Status'] is None:        sql = f"ALTER TABLE {row['Table']} ALTER {row['Column']} COMMENT {row['Comment']}; "        # idx = np.where(df["Status"] is None)        # idx = df.index[df['Status']]        idx = df.iloc[df['Status']]        empty_status_idx.append(idx)        print(f'idx: {idx}')        query_list.append(sql)query_list

I see the below error with idx:

TypeError: int() argument must be a string, a bytes-like object or a number, not 'NoneType'

What I want to see if a list of the positions of None cells:

empty_status_idx = [0, 2]

The above idx value I got from some of the answers from this stack overflow question